Base | Representation |
---|---|
bin | 111001111111011110000110… |
… | …110010110111100110111011 |
3 | 1020110001120102020112202212121 |
4 | 321333132012302313212323 |
5 | 231412221010412422113 |
6 | 2302240254201422111 |
7 | 104502530210233411 |
oct | 7177360662674673 |
9 | 1213046366482777 |
10 | 255050304420283 |
11 | 742a3254774459 |
12 | 2473255aa9a937 |
13 | ac411a9900878 |
14 | 46da7019092b1 |
15 | 1e7469c898e8d |
hex | e7f786cb79bb |
255050304420283 has 2 divisors, whose sum is σ = 255050304420284. Its totient is φ = 255050304420282.
The previous prime is 255050304420269. The next prime is 255050304420313. The reversal of 255050304420283 is 382024403050552.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 255050304420283 - 217 = 255050304289211 is a prime.
It is not a weakly prime, because it can be changed into another prime (255050304420683) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127525152210141 + 127525152210142.
It is an arithmetic number, because the mean of its divisors is an integer number (127525152210142).
Almost surely, 2255050304420283 is an apocalyptic number.
255050304420283 is a deficient number, since it is larger than the sum of its proper divisors (1).
255050304420283 is an equidigital number, since it uses as much as digits as its factorization.
255050304420283 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152000, while the sum is 43.
The spelling of 255050304420283 in words is "two hundred fifty-five trillion, fifty billion, three hundred four million, four hundred twenty thousand, two hundred eighty-three".
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