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255101040121 is a prime number
BaseRepresentation
bin1110110110010100110…
…1001111010111111001
3220101110102121112200011
43231211031033113321
513134421331240441
6313105232341521
724300433030564
oct3554515172771
9811412545604
10255101040121
1199207983194
12415349a48a1
131b095b36825
14c4c00954db
156980a7d581
hex3b6534f5f9

255101040121 has 2 divisors, whose sum is σ = 255101040122. Its totient is φ = 255101040120.

The previous prime is 255101040097. The next prime is 255101040151. The reversal of 255101040121 is 121040101552.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 248901210000 + 6199830121 = 498900^2 + 78739^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-255101040121 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 255101040092 and 255101040101.

It is not a weakly prime, because it can be changed into another prime (255101040151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127550520060 + 127550520061.

It is an arithmetic number, because the mean of its divisors is an integer number (127550520061).

Almost surely, 2255101040121 is an apocalyptic number.

It is an amenable number.

255101040121 is a deficient number, since it is larger than the sum of its proper divisors (1).

255101040121 is an equidigital number, since it uses as much as digits as its factorization.

255101040121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 400, while the sum is 22.

Adding to 255101040121 its reverse (121040101552), we get a palindrome (376141141673).

The spelling of 255101040121 in words is "two hundred fifty-five billion, one hundred one million, forty thousand, one hundred twenty-one".