Base | Representation |
---|---|
bin | 1110110110010100110… |
… | …1001111010111111001 |
3 | 220101110102121112200011 |
4 | 3231211031033113321 |
5 | 13134421331240441 |
6 | 313105232341521 |
7 | 24300433030564 |
oct | 3554515172771 |
9 | 811412545604 |
10 | 255101040121 |
11 | 99207983194 |
12 | 415349a48a1 |
13 | 1b095b36825 |
14 | c4c00954db |
15 | 6980a7d581 |
hex | 3b6534f5f9 |
255101040121 has 2 divisors, whose sum is σ = 255101040122. Its totient is φ = 255101040120.
The previous prime is 255101040097. The next prime is 255101040151. The reversal of 255101040121 is 121040101552.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 248901210000 + 6199830121 = 498900^2 + 78739^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-255101040121 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 255101040092 and 255101040101.
It is not a weakly prime, because it can be changed into another prime (255101040151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127550520060 + 127550520061.
It is an arithmetic number, because the mean of its divisors is an integer number (127550520061).
Almost surely, 2255101040121 is an apocalyptic number.
It is an amenable number.
255101040121 is a deficient number, since it is larger than the sum of its proper divisors (1).
255101040121 is an equidigital number, since it uses as much as digits as its factorization.
255101040121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 400, while the sum is 22.
Adding to 255101040121 its reverse (121040101552), we get a palindrome (376141141673).
The spelling of 255101040121 in words is "two hundred fifty-five billion, one hundred one million, forty thousand, one hundred twenty-one".
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