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255104433 = 32157180541
BaseRepresentation
bin11110011010010…
…01010110110001
3122210000122111100
433031021112301
51010301320213
641151435013
76215231463
oct1715112661
9583018440
10255104433
11120aaa811
1271525a69
1340b0bb8c
1425c48133
15175e1773
hexf3495b1

255104433 has 12 divisors (see below), whose sum is σ = 370833268. Its totient is φ = 168985440.

The previous prime is 255104389. The next prime is 255104441. The reversal of 255104433 is 334401552.

It can be written as a sum of positive squares in 2 ways, for example, as 55532304 + 199572129 = 7452^2 + 14127^2 .

It is not a de Polignac number, because 255104433 - 216 = 255038897 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 255104397 and 255104406.

It is not an unprimeable number, because it can be changed into a prime (255104453) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 88858 + ... + 91683.

Almost surely, 2255104433 is an apocalyptic number.

It is an amenable number.

255104433 is a deficient number, since it is larger than the sum of its proper divisors (115728835).

255104433 is a wasteful number, since it uses less digits than its factorization.

255104433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 180704 (or 180701 counting only the distinct ones).

The product of its (nonzero) digits is 7200, while the sum is 27.

The square root of 255104433 is about 15971.9890120173. The cubic root of 255104433 is about 634.2191265232.

Adding to 255104433 its reverse (334401552), we get a palindrome (589505985).

The spelling of 255104433 in words is "two hundred fifty-five million, one hundred four thousand, four hundred thirty-three".

Divisors: 1 3 9 157 471 1413 180541 541623 1624869 28344937 85034811 255104433