Base | Representation |
---|---|
bin | 100101000111111001000… |
… | …111100100100001011001 |
3 | 100000212211012112111012011 |
4 | 211013321013210201121 |
5 | 313244120322233123 |
6 | 5231542405545521 |
7 | 352211341500646 |
oct | 45077107444131 |
9 | 10025735474164 |
10 | 2551095117913 |
11 | 8a3a05761661 |
12 | 3525047152a1 |
13 | 15674b2b3614 |
14 | 8b68ba30dcd |
15 | 4655e6c4e0d |
hex | 251f91e4859 |
2551095117913 has 2 divisors, whose sum is σ = 2551095117914. Its totient is φ = 2551095117912.
The previous prime is 2551095117899. The next prime is 2551095118009. The reversal of 2551095117913 is 3197115901552.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1481997021129 + 1069098096784 = 1217373^2 + 1033972^2 .
It is a cyclic number.
It is not a de Polignac number, because 2551095117913 - 221 = 2551093020761 is a prime.
It is not a weakly prime, because it can be changed into another prime (2551095117013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1275547558956 + 1275547558957.
It is an arithmetic number, because the mean of its divisors is an integer number (1275547558957).
Almost surely, 22551095117913 is an apocalyptic number.
It is an amenable number.
2551095117913 is a deficient number, since it is larger than the sum of its proper divisors (1).
2551095117913 is an equidigital number, since it uses as much as digits as its factorization.
2551095117913 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 425250, while the sum is 49.
The spelling of 2551095117913 in words is "two trillion, five hundred fifty-one billion, ninety-five million, one hundred seventeen thousand, nine hundred thirteen".
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