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255113061939 = 32103992725829
BaseRepresentation
bin1110110110010111101…
…1000110011000110011
3220101111021020022111200
43231211323012120303
513134432420440224
6313110342142243
724300640150611
oct3554573063063
9811437208450
10255113061939
119921374437a
1241538a21983
131b098485728
14c4c19046b1
156981b555c9
hex3b65ec6633

255113061939 has 12 divisors (see below), whose sum is σ = 368532216000. Its totient is φ = 170058957264.

The previous prime is 255113061893. The next prime is 255113061961. The reversal of 255113061939 is 939160311552.

255113061939 is a `hidden beast` number, since 2 + 551 + 1 + 3 + 0 + 6 + 1 + 93 + 9 = 666.

It is not a de Polignac number, because 255113061939 - 27 = 255113061811 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 255113061894 and 255113061903.

It is not an unprimeable number, because it can be changed into a prime (255113065939) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1269324 + ... + 1456505.

It is an arithmetic number, because the mean of its divisors is an integer number (30711018000).

Almost surely, 2255113061939 is an apocalyptic number.

255113061939 is a deficient number, since it is larger than the sum of its proper divisors (113419154061).

255113061939 is a wasteful number, since it uses less digits than its factorization.

255113061939 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2736234 (or 2736231 counting only the distinct ones).

The product of its (nonzero) digits is 218700, while the sum is 45.

The spelling of 255113061939 in words is "two hundred fifty-five billion, one hundred thirteen million, sixty-one thousand, nine hundred thirty-nine".

Divisors: 1 3 9 10399 31197 93591 2725829 8177487 24532461 28345895771 85037687313 255113061939