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25514213041241 is a prime number
BaseRepresentation
bin1011100110100011111011…
…00110101110010001011001
310100100010122101010122112022
411303101331212232101121
511321011102014304431
6130133022340424225
75242224661353431
oct563217546562131
9110303571118468
1025514213041241
118147576120271
122a409aa3a8075
131130c97ca6b32
14642c747192c1
152e3a3ada207b
hex17347d9ae459

25514213041241 has 2 divisors, whose sum is σ = 25514213041242. Its totient is φ = 25514213041240.

The previous prime is 25514213041193. The next prime is 25514213041277. The reversal of 25514213041241 is 14214031241552.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 14877189553216 + 10637023488025 = 3857096^2 + 3261445^2 .

It is a cyclic number.

It is not a de Polignac number, because 25514213041241 - 222 = 25514208846937 is a prime.

It is a super-2 number, since 2×255142130412412 (a number of 28 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (25514213041441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12757106520620 + 12757106520621.

It is an arithmetic number, because the mean of its divisors is an integer number (12757106520621).

Almost surely, 225514213041241 is an apocalyptic number.

It is an amenable number.

25514213041241 is a deficient number, since it is larger than the sum of its proper divisors (1).

25514213041241 is an equidigital number, since it uses as much as digits as its factorization.

25514213041241 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 38400, while the sum is 35.

Adding to 25514213041241 its reverse (14214031241552), we get a palindrome (39728244282793).

The spelling of 25514213041241 in words is "twenty-five trillion, five hundred fourteen billion, two hundred thirteen million, forty-one thousand, two hundred forty-one".