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255144315100033 is a prime number
BaseRepresentation
bin111010000000110101101010…
…010001001001101110000001
31020110101120002000020010022101
4322000311222101021232001
5231420241024131200113
62302351402532510401
7104512365656644012
oct7200655221115601
91213346060203271
10255144315100033
117432a107303607
1224748816a7b401
13ac4a00c613618
14470109d33b009
151e76d50daa2dd
hexe80d6a449b81

255144315100033 has 2 divisors, whose sum is σ = 255144315100034. Its totient is φ = 255144315100032.

The previous prime is 255144315100019. The next prime is 255144315100063. The reversal of 255144315100033 is 330001513441552.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 249686517366784 + 5457797733249 = 15801472^2 + 2336193^2 .

It is a cyclic number.

It is not a de Polignac number, because 255144315100033 - 229 = 255143778229121 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 255144315099965 and 255144315100001.

It is not a weakly prime, because it can be changed into another prime (255144315100013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127572157550016 + 127572157550017.

It is an arithmetic number, because the mean of its divisors is an integer number (127572157550017).

Almost surely, 2255144315100033 is an apocalyptic number.

It is an amenable number.

255144315100033 is a deficient number, since it is larger than the sum of its proper divisors (1).

255144315100033 is an equidigital number, since it uses as much as digits as its factorization.

255144315100033 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 108000, while the sum is 37.

Adding to 255144315100033 its reverse (330001513441552), we get a palindrome (585145828541585).

The spelling of 255144315100033 in words is "two hundred fifty-five trillion, one hundred forty-four billion, three hundred fifteen million, one hundred thousand, thirty-three".