2553111331 has 4 divisors (see below), whose sum is σ = 2557536712. Its totient is φ = 2548685952.

The previous prime is 2553111317. The next prime is 2553111359. The reversal of 2553111331 is 1331113552.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2553111331 - 2⁷ = 2553111203 is a prime.

It is a super-2 number, since 2×2553111331² = 13036754936961183122, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2553111296 and 2553111305.

It is not an unprimeable number, because it can be changed into a prime (2553111311) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2211825 + ... + 2212978.

It is an arithmetic number, because the mean of its divisors is an integer number (639384178).

Almost surely, 2^2553111331 is an apocalyptic number.

2553111331 is a deficient number, since it is larger than the sum of its proper divisors (4425381).

2553111331 is an equidigital number, since it uses as much as digits as its factorization.

2553111331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4425380.

The product of its digits is 1350, while the sum is 25.

The square root of 2553111331 is about 50528.3220679254. The cubic root of 2553111331 is about 1366.7526281907.

Adding to 2553111331 its reverse (1331113552), we get a palindrome (3884224883).

The spelling of 2553111331 in words is "two billion, five hundred fifty-three million, one hundred eleven thousand, three hundred thirty-one".