2553130035 has 48 divisors (see below), whose sum is σ = 4665772800. Its totient is φ = 1287945792.

The previous prime is 2553130033. The next prime is 2553130037. The reversal of 2553130035 is 5300313552.

It is an interprime number because it is at equal distance from previous prime (2553130033) and next prime (2553130037).

It is not a de Polignac number, because 2553130035 - 2¹ = 2553130033 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2553129990 and 2553130008.

It is not an unprimeable number, because it can be changed into a prime (2553130033) by changing a digit.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 633256 + ... + 637274.

It is an arithmetic number, because the mean of its divisors is an integer number (97203600).

Almost surely, 2^2553130035 is an apocalyptic number.

2553130035 is a deficient number, since it is larger than the sum of its proper divisors (2112642765).

2553130035 is a wasteful number, since it uses less digits than its factorization.

2553130035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4792 (or 4789 counting only the distinct ones).

The product of its (nonzero) digits is 6750, while the sum is 27.

The square root of 2553130035 is about 50528.5071519039. The cubic root of 2553130035 is about 1366.7559657758.

Adding to 2553130035 its reverse (5300313552), we get a palindrome (7853443587).

The spelling of 2553130035 in words is "two billion, five hundred fifty-three million, one hundred thirty thousand, thirty-five".