Base | Representation |
---|---|
bin | 111010000011011010100001… |
… | …010100010101101000110001 |
3 | 1020111000110222122101200210021 |
4 | 322003122201110111220301 |
5 | 231431141042034410142 |
6 | 2303005000102403441 |
7 | 104531233426450345 |
oct | 7203324124255061 |
9 | 1214013878350707 |
10 | 255321332341297 |
11 | 74398194990a22 |
12 | 24776b99730581 |
13 | ac609102cc171 |
14 | 4709892d3b625 |
15 | 1e7b7617c8267 |
hex | e836a1515a31 |
255321332341297 has 2 divisors, whose sum is σ = 255321332341298. Its totient is φ = 255321332341296.
The previous prime is 255321332341291. The next prime is 255321332341511. The reversal of 255321332341297 is 792143233123552.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 165545252540721 + 89776079800576 = 12866439^2 + 9475024^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-255321332341297 is a prime.
It is not a weakly prime, because it can be changed into another prime (255321332341291) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127660666170648 + 127660666170649.
It is an arithmetic number, because the mean of its divisors is an integer number (127660666170649).
Almost surely, 2255321332341297 is an apocalyptic number.
It is an amenable number.
255321332341297 is a deficient number, since it is larger than the sum of its proper divisors (1).
255321332341297 is an equidigital number, since it uses as much as digits as its factorization.
255321332341297 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 8164800, while the sum is 52.
The spelling of 255321332341297 in words is "two hundred fifty-five trillion, three hundred twenty-one billion, three hundred thirty-two million, three hundred forty-one thousand, two hundred ninety-seven".
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