Base | Representation |
---|---|
bin | 1110110111001011101… |
… | …1101101010001001001 |
3 | 220102001110221020010210 |
4 | 3231302323231101021 |
5 | 13140404304400001 |
6 | 313144140231333 |
7 | 24306230311224 |
oct | 3556273552111 |
9 | 812043836123 |
10 | 255331325001 |
11 | 99315970675 |
12 | 41599b3b549 |
13 | 1b10176567c |
14 | c5028bc5bb |
15 | 6995dbadd6 |
hex | 3b72eed449 |
255331325001 has 16 divisors (see below), whose sum is σ = 347890176000. Its totient is φ = 166500949008.
The previous prime is 255331324949. The next prime is 255331325003. The reversal of 255331325001 is 100523133552.
It is not a de Polignac number, because 255331325001 - 215 = 255331292233 is a prime.
It is a super-3 number, since 3×2553313250013 (a number of 35 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 255331325001.
It is not an unprimeable number, because it can be changed into a prime (255331325003) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 293361 + ... + 772478.
It is an arithmetic number, because the mean of its divisors is an integer number (21743136000).
Almost surely, 2255331325001 is an apocalyptic number.
It is an amenable number.
255331325001 is a deficient number, since it is larger than the sum of its proper divisors (92558850999).
255331325001 is a wasteful number, since it uses less digits than its factorization.
255331325001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1067588.
The product of its (nonzero) digits is 13500, while the sum is 30.
Adding to 255331325001 its reverse (100523133552), we get a palindrome (355854458553).
The spelling of 255331325001 in words is "two hundred fifty-five billion, three hundred thirty-one million, three hundred twenty-five thousand, one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •