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255340433 is a prime number
BaseRepresentation
bin11110011100000…
…10111110010001
3122210110122020002
433032002332101
51010331343213
641200455345
76220233515
oct1716027621
9583418202
10255340433
11121151057
127161a555
1340b9241a
1425caa145
151763b658
hexf382f91

255340433 has 2 divisors, whose sum is σ = 255340434. Its totient is φ = 255340432.

The previous prime is 255340381. The next prime is 255340483. The reversal of 255340433 is 334043552.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 218093824 + 37246609 = 14768^2 + 6103^2 .

It is a cyclic number.

It is not a de Polignac number, because 255340433 - 26 = 255340369 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 255340396 and 255340405.

It is not a weakly prime, because it can be changed into another prime (255340483) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127670216 + 127670217.

It is an arithmetic number, because the mean of its divisors is an integer number (127670217).

Almost surely, 2255340433 is an apocalyptic number.

It is an amenable number.

255340433 is a deficient number, since it is larger than the sum of its proper divisors (1).

255340433 is an equidigital number, since it uses as much as digits as its factorization.

255340433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 21600, while the sum is 29.

The square root of 255340433 is about 15979.3752380999. The cubic root of 255340433 is about 634.4146406769.

Adding to 255340433 its reverse (334043552), we get a palindrome (589383985).

The spelling of 255340433 in words is "two hundred fifty-five million, three hundred forty thousand, four hundred thirty-three".