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2553505413001 is a prime number
BaseRepresentation
bin100101001010001000110…
…010000111011110001001
3100001010001011221011110121
4211022020302013132021
5313314034341204001
65233021510543241
7352325146613224
oct45121062073611
910033034834417
102553505413001
118a4a32265a74
12352a77967b21
13156a4376522a
148b839bb05bb
15466510d16a1
hex25288c87789

2553505413001 has 2 divisors, whose sum is σ = 2553505413002. Its totient is φ = 2553505413000.

The previous prime is 2553505412993. The next prime is 2553505413049. The reversal of 2553505413001 is 1003145053552.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2550009765625 + 3495647376 = 1596875^2 + 59124^2 .

It is a cyclic number.

It is not a de Polignac number, because 2553505413001 - 23 = 2553505412993 is a prime.

It is a super-3 number, since 3×25535054130013 (a number of 38 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (2553505413061) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1276752706500 + 1276752706501.

It is an arithmetic number, because the mean of its divisors is an integer number (1276752706501).

Almost surely, 22553505413001 is an apocalyptic number.

It is an amenable number.

2553505413001 is a deficient number, since it is larger than the sum of its proper divisors (1).

2553505413001 is an equidigital number, since it uses as much as digits as its factorization.

2553505413001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 45000, while the sum is 34.

The spelling of 2553505413001 in words is "two trillion, five hundred fifty-three billion, five hundred five million, four hundred thirteen thousand, one".