Base | Representation |
---|---|
bin | 111010000011111010010001… |
… | …111011110101111110011011 |
3 | 1020111010202000020200110112011 |
4 | 322003322101323311332123 |
5 | 231432220412101002113 |
6 | 2303032400015330351 |
7 | 104533551462664561 |
oct | 7203722173657633 |
9 | 1214122006613464 |
10 | 255355434000283 |
11 | 744006a4433071 |
12 | 247817162209b7 |
13 | ac63bb638a5c6 |
14 | 470b3a9ddda31 |
15 | 1e7c5aa55863d |
hex | e83e91ef5f9b |
255355434000283 has 2 divisors, whose sum is σ = 255355434000284. Its totient is φ = 255355434000282.
The previous prime is 255355434000263. The next prime is 255355434000361. The reversal of 255355434000283 is 382000434553552.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-255355434000283 is a prime.
It is not a weakly prime, because it can be changed into another prime (255355434000223) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127677717000141 + 127677717000142.
It is an arithmetic number, because the mean of its divisors is an integer number (127677717000142).
Almost surely, 2255355434000283 is an apocalyptic number.
255355434000283 is a deficient number, since it is larger than the sum of its proper divisors (1).
255355434000283 is an equidigital number, since it uses as much as digits as its factorization.
255355434000283 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8640000, while the sum is 49.
The spelling of 255355434000283 in words is "two hundred fifty-five trillion, three hundred fifty-five billion, four hundred thirty-four million, two hundred eighty-three", and thus it is an aban number.
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