Base | Representation |
---|---|
bin | 111010000011111010010110… |
… | …000111101101101100100011 |
3 | 1020111010202012010211001012002 |
4 | 322003322112013231230203 |
5 | 231432221033040032323 |
6 | 2303032411004354215 |
7 | 104533553304600566 |
oct | 7203722607555443 |
9 | 1214122163731162 |
10 | 255355504220963 |
11 | 74400730034993 |
12 | 2478173584596b |
13 | ac63bc7aa56c3 |
14 | 470b3b547c4dd |
15 | 1e7c5b17c9828 |
hex | e83e961edb23 |
255355504220963 has 2 divisors, whose sum is σ = 255355504220964. Its totient is φ = 255355504220962.
The previous prime is 255355504220911. The next prime is 255355504221029. The reversal of 255355504220963 is 369022405553552.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 255355504220963 - 230 = 255354430479139 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 255355504220899 and 255355504220908.
It is not a weakly prime, because it can be changed into another prime (255355504229963) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127677752110481 + 127677752110482.
It is an arithmetic number, because the mean of its divisors is an integer number (127677752110482).
Almost surely, 2255355504220963 is an apocalyptic number.
255355504220963 is a deficient number, since it is larger than the sum of its proper divisors (1).
255355504220963 is an equidigital number, since it uses as much as digits as its factorization.
255355504220963 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48600000, while the sum is 56.
The spelling of 255355504220963 in words is "two hundred fifty-five trillion, three hundred fifty-five billion, five hundred four million, two hundred twenty thousand, nine hundred sixty-three".
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