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255435396113 is a prime number
BaseRepresentation
bin1110110111100100100…
…0101101010000010001
3220102022201202120212102
43231321020231100101
513141112430133423
6313202335010145
724311633020442
oct3557110552021
9812281676772
10255435396113
1199369692857
1241608969955
131b11a1a3201
14c51264d2c9
1569a00c6c28
hex3b7922d411

255435396113 has 2 divisors, whose sum is σ = 255435396114. Its totient is φ = 255435396112.

The previous prime is 255435396091. The next prime is 255435396131. The reversal of 255435396113 is 311693534552.

Together with next prime (255435396131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 254629233664 + 806162449 = 504608^2 + 28393^2 .

It is a cyclic number.

It is not a de Polignac number, because 255435396113 - 230 = 254361654289 is a prime.

It is not a weakly prime, because it can be changed into another prime (255435396143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127717698056 + 127717698057.

It is an arithmetic number, because the mean of its divisors is an integer number (127717698057).

Almost surely, 2255435396113 is an apocalyptic number.

It is an amenable number.

255435396113 is a deficient number, since it is larger than the sum of its proper divisors (1).

255435396113 is an equidigital number, since it uses as much as digits as its factorization.

255435396113 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1458000, while the sum is 47.

The spelling of 255435396113 in words is "two hundred fifty-five billion, four hundred thirty-five million, three hundred ninety-six thousand, one hundred thirteen".