Base | Representation |
---|---|
bin | 1110110111100110000… |
… | …0100111110001101011 |
3 | 220102100011120002100021 |
4 | 3231321200213301223 |
5 | 13141121031241011 |
6 | 313203121221311 |
7 | 24312040220452 |
oct | 3557140476153 |
9 | 812304502307 |
10 | 255441665131 |
11 | 99372184864 |
12 | 4160aa91837 |
13 | 1b11b5897a3 |
14 | c513401b99 |
15 | 69a0914471 |
hex | 3b79827c6b |
255441665131 has 2 divisors, whose sum is σ = 255441665132. Its totient is φ = 255441665130.
The previous prime is 255441665107. The next prime is 255441665159. The reversal of 255441665131 is 131566144552.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 255441665131 - 25 = 255441665099 is a prime.
It is a super-2 number, since 2×2554416651312 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (255441665161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127720832565 + 127720832566.
It is an arithmetic number, because the mean of its divisors is an integer number (127720832566).
Almost surely, 2255441665131 is an apocalyptic number.
255441665131 is a deficient number, since it is larger than the sum of its proper divisors (1).
255441665131 is an equidigital number, since it uses as much as digits as its factorization.
255441665131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 432000, while the sum is 43.
The spelling of 255441665131 in words is "two hundred fifty-five billion, four hundred forty-one million, six hundred sixty-five thousand, one hundred thirty-one".
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