Base | Representation |
---|---|
bin | 1011100111011110001101… |
… | …01010000010111011100011 |
3 | 10100110010102001111120222011 |
4 | 11303233012222002323203 |
5 | 11322014142333421011 |
6 | 130155235310053351 |
7 | 5244413250242032 |
oct | 563570652027343 |
9 | 110403361446864 |
10 | 25545503420131 |
11 | 8159872790032 |
12 | 2a46a814aa257 |
13 | 1133c137b8926 |
14 | 6445a229c719 |
15 | 2e476ce1a621 |
hex | 173bc6a82ee3 |
25545503420131 has 2 divisors, whose sum is σ = 25545503420132. Its totient is φ = 25545503420130.
The previous prime is 25545503420123. The next prime is 25545503420147. The reversal of 25545503420131 is 13102430554552.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 25545503420131 - 23 = 25545503420123 is a prime.
It is a super-2 number, since 2×255455034201312 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (25545503420111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12772751710065 + 12772751710066.
It is an arithmetic number, because the mean of its divisors is an integer number (12772751710066).
Almost surely, 225545503420131 is an apocalyptic number.
25545503420131 is a deficient number, since it is larger than the sum of its proper divisors (1).
25545503420131 is an equidigital number, since it uses as much as digits as its factorization.
25545503420131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 360000, while the sum is 40.
Adding to 25545503420131 its reverse (13102430554552), we get a palindrome (38647933974683).
The spelling of 25545503420131 in words is "twenty-five trillion, five hundred forty-five billion, five hundred three million, four hundred twenty thousand, one hundred thirty-one".
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