Base | Representation |
---|---|
bin | 1110111000010001010… |
… | …0101000111010000011 |
3 | 220102210210220120201110 |
4 | 3232010110220322003 |
5 | 13142004001322121 |
6 | 313233121334403 |
7 | 24316402162536 |
oct | 3560424507203 |
9 | 812723816643 |
10 | 255623073411 |
11 | 99455619562 |
12 | 4165b797403 |
13 | 1b14a034674 |
14 | c52d544a1d |
15 | 69b17e9d76 |
hex | 3b84528e83 |
255623073411 has 16 divisors (see below), whose sum is σ = 358789616640. Its totient is φ = 161436975840.
The previous prime is 255623073397. The next prime is 255623073457. The reversal of 255623073411 is 114370326552.
It is not a de Polignac number, because 255623073411 - 213 = 255623065219 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 255623073411.
It is not an unprimeable number, because it can be changed into a prime (255623073481) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 965806 + ... + 1201676.
It is an arithmetic number, because the mean of its divisors is an integer number (22424351040).
Almost surely, 2255623073411 is an apocalyptic number.
255623073411 is a deficient number, since it is larger than the sum of its proper divisors (103166543229).
255623073411 is a wasteful number, since it uses less digits than its factorization.
255623073411 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 254906.
The product of its (nonzero) digits is 151200, while the sum is 39.
Adding to 255623073411 its reverse (114370326552), we get a palindrome (369993399963).
The spelling of 255623073411 in words is "two hundred fifty-five billion, six hundred twenty-three million, seventy-three thousand, four hundred eleven".
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