25564321403131 has 8 divisors (see below), whose sum is σ = 29224646282720. Its totient is φ = 21906066264768.

The previous prime is 25564321403119. The next prime is 25564321403161. The reversal of 25564321403131 is 13130412346552.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 25564321403131 - 2⁷ = 25564321403003 is a prime.

It is a super-2 number, since 2×25564321403131² (a number of 28 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (25564321403111) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 517408836 + ... + 517458241.

It is an arithmetic number, because the mean of its divisors is an integer number (3653080785340).

Almost surely, 2^{25564321403131} is an apocalyptic number.

25564321403131 is a deficient number, since it is larger than the sum of its proper divisors (3660324879589).

25564321403131 is a wasteful number, since it uses less digits than its factorization.

25564321403131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1034870613.

The product of its (nonzero) digits is 259200, while the sum is 40.

Adding to 25564321403131 its reverse (13130412346552), we get a palindrome (38694733749683).

The spelling of 25564321403131 in words is "twenty-five trillion, five hundred sixty-four billion, three hundred twenty-one million, four hundred three thousand, one hundred thirty-one".