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255684974401 = 659387989339
BaseRepresentation
bin1110111000100000000…
…0110001011101000001
3220102222010101110220201
43232020000301131001
513142120323140101
6313243212205201
724321053265103
oct3561000613501
9812863343821
10255684974401
11994875586aa
1241678469801
131b159ac897c
14c537859573
1569b6e75e01
hex3b88031741

255684974401 has 4 divisors (see below), whose sum is σ = 256072964400. Its totient is φ = 255296984404.

The previous prime is 255684974351. The next prime is 255684974459. The reversal of 255684974401 is 104479486552.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 255684974401 - 219 = 255684450113 is a prime.

It is a super-2 number, since 2×2556849744012 (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (255684974491) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 193994011 + ... + 193995328.

It is an arithmetic number, because the mean of its divisors is an integer number (64018241100).

Almost surely, 2255684974401 is an apocalyptic number.

It is an amenable number.

255684974401 is a deficient number, since it is larger than the sum of its proper divisors (387989999).

255684974401 is an equidigital number, since it uses as much as digits as its factorization.

255684974401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 387989998.

The product of its (nonzero) digits is 9676800, while the sum is 55.

The spelling of 255684974401 in words is "two hundred fifty-five billion, six hundred eighty-four million, nine hundred seventy-four thousand, four hundred one".

Divisors: 1 659 387989339 255684974401