Base | Representation |
---|---|
bin | 1110111000100000000… |
… | …0110001011101000001 |
3 | 220102222010101110220201 |
4 | 3232020000301131001 |
5 | 13142120323140101 |
6 | 313243212205201 |
7 | 24321053265103 |
oct | 3561000613501 |
9 | 812863343821 |
10 | 255684974401 |
11 | 994875586aa |
12 | 41678469801 |
13 | 1b159ac897c |
14 | c537859573 |
15 | 69b6e75e01 |
hex | 3b88031741 |
255684974401 has 4 divisors (see below), whose sum is σ = 256072964400. Its totient is φ = 255296984404.
The previous prime is 255684974351. The next prime is 255684974459. The reversal of 255684974401 is 104479486552.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 255684974401 - 219 = 255684450113 is a prime.
It is a super-2 number, since 2×2556849744012 (a number of 24 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (255684974491) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 193994011 + ... + 193995328.
It is an arithmetic number, because the mean of its divisors is an integer number (64018241100).
Almost surely, 2255684974401 is an apocalyptic number.
It is an amenable number.
255684974401 is a deficient number, since it is larger than the sum of its proper divisors (387989999).
255684974401 is an equidigital number, since it uses as much as digits as its factorization.
255684974401 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 387989998.
The product of its (nonzero) digits is 9676800, while the sum is 55.
The spelling of 255684974401 in words is "two hundred fifty-five billion, six hundred eighty-four million, nine hundred seventy-four thousand, four hundred one".
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