Base | Representation |
---|---|
bin | 110000110001… |
… | …0111011100001 |
3 | 1210010010212121 |
4 | 1201202323201 |
5 | 23021233131 |
6 | 2312024241 |
7 | 430231066 |
oct | 141427341 |
9 | 53103777 |
10 | 25571041 |
11 | 134859a1 |
12 | 8692081 |
13 | 53b40c2 |
14 | 3578c6d |
15 | 23a1911 |
hex | 1862ee1 |
25571041 has 2 divisors, whose sum is σ = 25571042. Its totient is φ = 25571040.
The previous prime is 25571023. The next prime is 25571053. The reversal of 25571041 is 14017552.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 23970816 + 1600225 = 4896^2 + 1265^2 .
It is a cyclic number.
It is not a de Polignac number, because 25571041 - 211 = 25568993 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 25570997 and 25571015.
It is not a weakly prime, because it can be changed into another prime (25571081) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12785520 + 12785521.
It is an arithmetic number, because the mean of its divisors is an integer number (12785521).
Almost surely, 225571041 is an apocalyptic number.
It is an amenable number.
25571041 is a deficient number, since it is larger than the sum of its proper divisors (1).
25571041 is an equidigital number, since it uses as much as digits as its factorization.
25571041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1400, while the sum is 25.
The square root of 25571041 is about 5056.7816840358. The cubic root of 25571041 is about 294.6113468480.
Adding to 25571041 its reverse (14017552), we get a palindrome (39588593).
The spelling of 25571041 in words is "twenty-five million, five hundred seventy-one thousand, forty-one".
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