255715113001 has 2 divisors, whose sum is σ = 255715113002. Its totient is φ = 255715113000.

The previous prime is 255715112987. The next prime is 255715113011. The reversal of 255715113001 is 100311517552.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 254141007376 + 1574105625 = 504124^2 + 39675^2 .

It is a cyclic number.

It is not a de Polignac number, because 255715113001 - 2¹³ = 255715104809 is a prime.

It is a super-2 number, since 2×255715113001² (a number of 24 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (255715113011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127857556500 + 127857556501.

It is an arithmetic number, because the mean of its divisors is an integer number (127857556501).

Almost surely, 2^255715113001 is an apocalyptic number.

It is an amenable number.

255715113001 is a deficient number, since it is larger than the sum of its proper divisors (1).

255715113001 is an equidigital number, since it uses as much as digits as its factorization.

255715113001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5250, while the sum is 31.

The spelling of 255715113001 in words is "two hundred fifty-five billion, seven hundred fifteen million, one hundred thirteen thousand, one".