Base | Representation |
---|---|
bin | 1001110000010111111001 |
3 | 11210221010202 |
4 | 21300113321 |
5 | 1123314213 |
6 | 130451545 |
7 | 30511034 |
oct | 11602771 |
9 | 4727122 |
10 | 2557433 |
11 | 149748a |
12 | a33bb5 |
13 | 6b7098 |
14 | 4a801b |
15 | 357b58 |
hex | 2705f9 |
2557433 has 2 divisors, whose sum is σ = 2557434. Its totient is φ = 2557432.
The previous prime is 2557417. The next prime is 2557441. The reversal of 2557433 is 3347552.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2111209 + 446224 = 1453^2 + 668^2 .
It is a cyclic number.
It is not a de Polignac number, because 2557433 - 24 = 2557417 is a prime.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 2557396 and 2557405.
It is not a weakly prime, because it can be changed into another prime (2557453) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1278716 + 1278717.
It is an arithmetic number, because the mean of its divisors is an integer number (1278717).
22557433 is an apocalyptic number.
It is an amenable number.
2557433 is a deficient number, since it is larger than the sum of its proper divisors (1).
2557433 is an equidigital number, since it uses as much as digits as its factorization.
2557433 is an evil number, because the sum of its binary digits is even.
The product of its digits is 12600, while the sum is 29.
The square root of 2557433 is about 1599.1976113039. The cubic root of 2557433 is about 136.7523363983.
The spelling of 2557433 in words is "two million, five hundred fifty-seven thousand, four hundred thirty-three".
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