Base | Representation |
---|---|
bin | 1110111001101011001… |
… | …0100000001010001011 |
3 | 220110210002011110200121 |
4 | 3232122302200022023 |
5 | 13143242000010101 |
6 | 313334344244111 |
7 | 24331630050013 |
oct | 3563262401213 |
9 | 813702143617 |
10 | 256000000651 |
11 | 9962936557a |
12 | 41745a70637 |
13 | 1b1aa158035 |
14 | c567620c43 |
15 | 69d49520a1 |
hex | 3b9aca028b |
256000000651 has 4 divisors (see below), whose sum is σ = 256007507400. Its totient is φ = 255992493904.
The previous prime is 256000000559. The next prime is 256000000667. The reversal of 256000000651 is 156000000652.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-256000000651 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (256000000681) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3701986 + ... + 3770503.
It is an arithmetic number, because the mean of its divisors is an integer number (64001876850).
Almost surely, 2256000000651 is an apocalyptic number.
256000000651 is a deficient number, since it is larger than the sum of its proper divisors (7506749).
256000000651 is an equidigital number, since it uses as much as digits as its factorization.
256000000651 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7506748.
The product of its (nonzero) digits is 1800, while the sum is 25.
Subtracting from 256000000651 its reverse (156000000652), we obtain a palindrome (99999999999).
The spelling of 256000000651 in words is "two hundred fifty-six billion, six hundred fifty-one", and thus it is an aban number.
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