Base | Representation |
---|---|
bin | 100101010001001001000… |
… | …011111011000110000011 |
3 | 100001211110022202110202122 |
4 | 211101021003323012003 |
5 | 313424440211224132 |
6 | 5240304053034455 |
7 | 353012422101551 |
oct | 45211103730603 |
9 | 10054408673678 |
10 | 2561026273667 |
11 | 8a81416249a4 |
12 | 354416625a2b |
13 | 157671948344 |
14 | 8bd50992bd1 |
15 | 469414d4912 |
hex | 254490fb183 |
2561026273667 has 4 divisors (see below), whose sum is σ = 2575829893920. Its totient is φ = 2546222653416.
The previous prime is 2561026273657. The next prime is 2561026273669. The reversal of 2561026273667 is 7663726201652.
2561026273667 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2561026273667 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2561026273669) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7401809867 + ... + 7401810212.
It is an arithmetic number, because the mean of its divisors is an integer number (643957473480).
Almost surely, 22561026273667 is an apocalyptic number.
2561026273667 is a deficient number, since it is larger than the sum of its proper divisors (14803620253).
2561026273667 is a wasteful number, since it uses less digits than its factorization.
2561026273667 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14803620252.
The product of its (nonzero) digits is 7620480, while the sum is 53.
The spelling of 2561026273667 in words is "two trillion, five hundred sixty-one billion, twenty-six million, two hundred seventy-three thousand, six hundred sixty-seven".
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