Base | Representation |
---|---|
bin | 100101010001011100001… |
… | …110110110010110110001 |
3 | 100001212021201222000221012 |
4 | 211101130032312112301 |
5 | 313431120030424240 |
6 | 5240400022440305 |
7 | 353023405653224 |
oct | 45213416662661 |
9 | 10055251860835 |
10 | 2561347904945 |
11 | 8a8297133275 |
12 | 3544a6293095 |
13 | 1576c347abcb |
14 | 8bd815975bb |
15 | 4695e867b65 |
hex | 2545c3b65b1 |
2561347904945 has 32 divisors (see below), whose sum is σ = 3193289049600. Its totient is φ = 1970827780096.
The previous prime is 2561347904849. The next prime is 2561347904981. The reversal of 2561347904945 is 5494097431652.
2561347904945 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 2561347904945 - 230 = 2560274163121 is a prime.
It is a super-2 number, since 2×25613479049452 (a number of 26 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (59).
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 43465061 + ... + 43523949.
It is an arithmetic number, because the mean of its divisors is an integer number (99790282800).
Almost surely, 22561347904945 is an apocalyptic number.
It is an amenable number.
2561347904945 is a deficient number, since it is larger than the sum of its proper divisors (631941144655).
2561347904945 is a wasteful number, since it uses less digits than its factorization.
2561347904945 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 62137.
The product of its (nonzero) digits is 32659200, while the sum is 59.
The spelling of 2561347904945 in words is "two trillion, five hundred sixty-one billion, three hundred forty-seven million, nine hundred four thousand, nine hundred forty-five".
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