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2561681047537 is a prime number
BaseRepresentation
bin100101010001110000000…
…101101011111111110001
3100001220010221211102122201
4211101300011223333301
5313432310322010122
65240453043103201
7353034562430353
oct45216005537761
910056127742581
102561681047537
118a8448194227
12354579971b01
131577474b11c1
148bdb39170d3
154697dc21a27
hex2547016bff1

2561681047537 has 2 divisors, whose sum is σ = 2561681047538. Its totient is φ = 2561681047536.

The previous prime is 2561681047477. The next prime is 2561681047543. The reversal of 2561681047537 is 7357401861652.

2561681047537 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2541725529841 + 19955517696 = 1594279^2 + 141264^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2561681047537 is a prime.

It is not a weakly prime, because it can be changed into another prime (2561681047547) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1280840523768 + 1280840523769.

It is an arithmetic number, because the mean of its divisors is an integer number (1280840523769).

Almost surely, 22561681047537 is an apocalyptic number.

It is an amenable number.

2561681047537 is a deficient number, since it is larger than the sum of its proper divisors (1).

2561681047537 is an equidigital number, since it uses as much as digits as its factorization.

2561681047537 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8467200, while the sum is 55.

The spelling of 2561681047537 in words is "two trillion, five hundred sixty-one billion, six hundred eighty-one million, forty-seven thousand, five hundred thirty-seven".