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2564128233339 = 3854709411113
BaseRepresentation
bin100101010100000001111…
…100111101011101111011
3100002010110111122100110220
4211110001330331131323
5314002313311431324
65241535542511123
7353152326241011
oct45240174753573
910063414570426
102564128233339
118a94935a5132
12354b414354a3
13157a474ab33a
148c16693a8b1
1546a739b8b79
hex25501f3d77b

2564128233339 has 4 divisors (see below), whose sum is σ = 3418837644456. Its totient is φ = 1709418822224.

The previous prime is 2564128233319. The next prime is 2564128233341. The reversal of 2564128233339 is 9333328214652.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2564128233339 - 25 = 2564128233307 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2564128233291 and 2564128233300.

It is not an unprimeable number, because it can be changed into a prime (2564128233319) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 427354705554 + ... + 427354705559.

It is an arithmetic number, because the mean of its divisors is an integer number (854709411114).

Almost surely, 22564128233339 is an apocalyptic number.

2564128233339 is a deficient number, since it is larger than the sum of its proper divisors (854709411117).

2564128233339 is an equidigital number, since it uses as much as digits as its factorization.

2564128233339 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 854709411116.

The product of its digits is 5598720, while the sum is 51.

The spelling of 2564128233339 in words is "two trillion, five hundred sixty-four billion, one hundred twenty-eight million, two hundred thirty-three thousand, three hundred thirty-nine".

Divisors: 1 3 854709411113 2564128233339