Base | Representation |
---|---|
bin | 10111111010001100… |
… | …000111000110101011 |
3 | 2110021010222202000212 |
4 | 113322030013012223 |
5 | 410034103042212 |
6 | 15443234451335 |
7 | 1566120036212 |
oct | 277214070653 |
9 | 73233882025 |
10 | 25672315307 |
11 | a984397511 |
12 | 4b85733b4b |
13 | 2561901722 |
14 | 1357796079 |
15 | a03c26e22 |
hex | 5fa3071ab |
25672315307 has 2 divisors, whose sum is σ = 25672315308. Its totient is φ = 25672315306.
The previous prime is 25672315301. The next prime is 25672315423. The reversal of 25672315307 is 70351327652.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-25672315307 is a prime.
It is not a weakly prime, because it can be changed into another prime (25672315301) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12836157653 + 12836157654.
It is an arithmetic number, because the mean of its divisors is an integer number (12836157654).
Almost surely, 225672315307 is an apocalyptic number.
25672315307 is a deficient number, since it is larger than the sum of its proper divisors (1).
25672315307 is an equidigital number, since it uses as much as digits as its factorization.
25672315307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 264600, while the sum is 41.
The spelling of 25672315307 in words is "twenty-five billion, six hundred seventy-two million, three hundred fifteen thousand, three hundred seven".
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