Base | Representation |
---|---|
bin | 100101011000011101010… |
… | …100111011000100101001 |
3 | 100002120201211120110011021 |
4 | 211120131110323010221 |
5 | 314042032402421423 |
6 | 5244043414332441 |
7 | 353411205455614 |
oct | 45303524730451 |
9 | 10076654513137 |
10 | 2568882467113 |
11 | 900503200356 |
12 | 355a4965a121 |
13 | 15832444a611 |
14 | 8c49810517b |
15 | 46c5107595d |
hex | 2561d53b129 |
2568882467113 has 4 divisors (see below), whose sum is σ = 2568931161028. Its totient is φ = 2568833773200.
The previous prime is 2568882467071. The next prime is 2568882467117. The reversal of 2568882467113 is 3117642888652.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 12618702889 + 2556263764224 = 112333^2 + 1598832^2 .
It is a cyclic number.
It is not a de Polignac number, because 2568882467113 - 221 = 2568880369961 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2568882467117) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24267738 + ... + 24373363.
It is an arithmetic number, because the mean of its divisors is an integer number (642232790257).
Almost surely, 22568882467113 is an apocalyptic number.
It is an amenable number.
2568882467113 is a deficient number, since it is larger than the sum of its proper divisors (48693915).
2568882467113 is an equidigital number, since it uses as much as digits as its factorization.
2568882467113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 48693914.
The product of its digits is 30965760, while the sum is 61.
The spelling of 2568882467113 in words is "two trillion, five hundred sixty-eight billion, eight hundred eighty-two million, four hundred sixty-seven thousand, one hundred thirteen".
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