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256920043 = 594354577
BaseRepresentation
bin11110101000001…
…00100111101011
3122220102220001011
433110010213223
51011232420133
641254404351
76236533012
oct1724044753
9586386034
10256920043
1112202a916
12720606b7
13412c63c3
142619ba79
151784e6cd
hexf5049eb

256920043 has 4 divisors (see below), whose sum is σ = 261274680. Its totient is φ = 252565408.

The previous prime is 256920029. The next prime is 256920047. The reversal of 256920043 is 340029652.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-256920043 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 256919987 and 256920014.

It is not an unprimeable number, because it can be changed into a prime (256920047) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2177230 + ... + 2177347.

It is an arithmetic number, because the mean of its divisors is an integer number (65318670).

Almost surely, 2256920043 is an apocalyptic number.

256920043 is a deficient number, since it is larger than the sum of its proper divisors (4354637).

256920043 is an equidigital number, since it uses as much as digits as its factorization.

256920043 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4354636.

The product of its (nonzero) digits is 12960, while the sum is 31.

The square root of 256920043 is about 16028.7255575732. The cubic root of 256920043 is about 635.7201765681.

Adding to 256920043 its reverse (340029652), we get a palindrome (596949695).

The spelling of 256920043 in words is "two hundred fifty-six million, nine hundred twenty thousand, forty-three".

Divisors: 1 59 4354577 256920043