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257065634416121 = 476177353985277
BaseRepresentation
bin111010011100110011000001…
…110100101100010111111001
31020201012020100001111002201022
4322130303001310230113321
5232143230404402303441
62310422153325432225
7105101244030451046
oct7234630164542771
91221166301432638
10257065634416121
11749aaa17a38a93
12249b9060a0b675
13b059254181b9b
14476a0863601cd
151eabd0162284b
hexe9ccc1d2c5f9

257065634416121 has 4 divisors (see below), whose sum is σ = 257065693163172. Its totient is φ = 257065575669072.

The previous prime is 257065634416117. The next prime is 257065634416147. The reversal of 257065634416121 is 121614436560752.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 114858483012025 + 142207151404096 = 10717205^2 + 11925064^2 .

It is a cyclic number.

It is not a de Polignac number, because 257065634416121 - 22 = 257065634416117 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (257065634416321) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22230866 + ... + 31754411.

It is an arithmetic number, because the mean of its divisors is an integer number (64266423290793).

Almost surely, 2257065634416121 is an apocalyptic number.

It is an amenable number.

257065634416121 is a deficient number, since it is larger than the sum of its proper divisors (58747051).

257065634416121 is an equidigital number, since it uses as much as digits as its factorization.

257065634416121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 58747050.

The product of its (nonzero) digits is 7257600, while the sum is 53.

The spelling of 257065634416121 in words is "two hundred fifty-seven trillion, sixty-five billion, six hundred thirty-four million, four hundred sixteen thousand, one hundred twenty-one".

Divisors: 1 4761773 53985277 257065634416121