Base | Representation |
---|---|
bin | 1110111110000000111… |
… | …0000010101101111001 |
3 | 220120210021000211211202 |
4 | 3233200032002231321 |
5 | 13203133200113433 |
6 | 314050115103545 |
7 | 24402533066264 |
oct | 3574016025571 |
9 | 816707024752 |
10 | 257164847993 |
11 | 9a076941629 |
12 | 41a0bba1bb5 |
13 | 1b334592111 |
14 | c6381ddcdb |
15 | 6a51d46ee8 |
hex | 3be0382b79 |
257164847993 has 2 divisors, whose sum is σ = 257164847994. Its totient is φ = 257164847992.
The previous prime is 257164847977. The next prime is 257164848037. The reversal of 257164847993 is 399748461752.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 253540446784 + 3624401209 = 503528^2 + 60203^2 .
It is a cyclic number.
It is not a de Polignac number, because 257164847993 - 24 = 257164847977 is a prime.
It is a super-2 number, since 2×2571648479932 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (257164847293) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 128582423996 + 128582423997.
It is an arithmetic number, because the mean of its divisors is an integer number (128582423997).
Almost surely, 2257164847993 is an apocalyptic number.
It is an amenable number.
257164847993 is a deficient number, since it is larger than the sum of its proper divisors (1).
257164847993 is an equidigital number, since it uses as much as digits as its factorization.
257164847993 is an evil number, because the sum of its binary digits is even.
The product of its digits is 91445760, while the sum is 65.
The spelling of 257164847993 in words is "two hundred fifty-seven billion, one hundred sixty-four million, eight hundred forty-seven thousand, nine hundred ninety-three".
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