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2580770486713 is a prime number
BaseRepresentation
bin100101100011100001111…
…010000111100110111001
3100010201102022222102021111
4211203201322013212321
5314240404221033323
65253331204040321
7354311620122106
oct45434172074671
910121368872244
102580770486713
11905553728441
123582069930a1
1315949a335543
148cca4cd3aad
15471e9a76c0d
hex258e1e879b9

2580770486713 has 2 divisors, whose sum is σ = 2580770486714. Its totient is φ = 2580770486712.

The previous prime is 2580770486669. The next prime is 2580770486743. The reversal of 2580770486713 is 3176840770852.

2580770486713 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2559753605929 + 21016880784 = 1599923^2 + 144972^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2580770486713 is a prime.

It is not a weakly prime, because it can be changed into another prime (2580770486743) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1290385243356 + 1290385243357.

It is an arithmetic number, because the mean of its divisors is an integer number (1290385243357).

Almost surely, 22580770486713 is an apocalyptic number.

It is an amenable number.

2580770486713 is a deficient number, since it is larger than the sum of its proper divisors (1).

2580770486713 is an equidigital number, since it uses as much as digits as its factorization.

2580770486713 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15805440, while the sum is 58.

The spelling of 2580770486713 in words is "two trillion, five hundred eighty billion, seven hundred seventy million, four hundred eighty-six thousand, seven hundred thirteen".