Base | Representation |
---|---|
bin | 1011101111010001011111… |
… | …01001111111111111100011 |
3 | 10101101202021220001111121221 |
4 | 11313220233221333333203 |
5 | 11340412124031110011 |
6 | 130522325454355511 |
7 | 5302652623052026 |
oct | 567505751777743 |
9 | 111352256044557 |
10 | 25813552988131 |
11 | 8252514781927 |
12 | 2a8aa0a7bbb97 |
13 | 115329114196c |
14 | 65354dd211bd |
15 | 2eb70a62e971 |
hex | 177a2fa7ffe3 |
25813552988131 has 2 divisors, whose sum is σ = 25813552988132. Its totient is φ = 25813552988130.
The previous prime is 25813552988051. The next prime is 25813552988203. The reversal of 25813552988131 is 13188925531852.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 25813552988131 - 223 = 25813544599523 is a prime.
It is a super-2 number, since 2×258135529881312 (a number of 28 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 25813552988131.
It is not a weakly prime, because it can be changed into another prime (25813552988231) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12906776494065 + 12906776494066.
It is an arithmetic number, because the mean of its divisors is an integer number (12906776494066).
Almost surely, 225813552988131 is an apocalyptic number.
25813552988131 is a deficient number, since it is larger than the sum of its proper divisors (1).
25813552988131 is an equidigital number, since it uses as much as digits as its factorization.
25813552988131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 20736000, while the sum is 61.
The spelling of 25813552988131 in words is "twenty-five trillion, eight hundred thirteen billion, five hundred fifty-two million, nine hundred eighty-eight thousand, one hundred thirty-one".
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