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2582540113 is a prime number
BaseRepresentation
bin1001100111101110…
…0110111101010001
320122222111122000211
42121323212331101
520242112240423
61104132444121
7120666141316
oct23173467521
96588448024
102582540113
11110585a67a
12600a79641
1332206ba5a
141a6db8d0d
15101ad210d
hex99ee6f51

2582540113 has 2 divisors, whose sum is σ = 2582540114. Its totient is φ = 2582540112.

The previous prime is 2582540087. The next prime is 2582540179. The reversal of 2582540113 is 3110452852.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1582209729 + 1000330384 = 39777^2 + 31628^2 .

It is a cyclic number.

It is not a de Polignac number, because 2582540113 - 217 = 2582409041 is a prime.

It is not a weakly prime, because it can be changed into another prime (2582541113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1291270056 + 1291270057.

It is an arithmetic number, because the mean of its divisors is an integer number (1291270057).

Almost surely, 22582540113 is an apocalyptic number.

It is an amenable number.

2582540113 is a deficient number, since it is larger than the sum of its proper divisors (1).

2582540113 is an equidigital number, since it uses as much as digits as its factorization.

2582540113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9600, while the sum is 31.

The square root of 2582540113 is about 50818.6984583431. The cubic root of 2582540113 is about 1371.9839324207.

Adding to 2582540113 its reverse (3110452852), we get a palindrome (5692992965).

The spelling of 2582540113 in words is "two billion, five hundred eighty-two million, five hundred forty thousand, one hundred thirteen".