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2585344350071 = 73179150810497
BaseRepresentation
bin100101100111110010100…
…010000001011101110111
3100011011020002111202021002
4211213302202001131313
5314324241123200241
65255405113513515
7354533146246520
oct45476242013567
910134202452232
102585344350071
119074905386aa
1235908271289b
13159a48b01172
148d1ba549847
15473b63a589b
hex259f2881777

2585344350071 has 16 divisors (see below), whose sum is σ = 3088598999040. Its totient is φ = 2117379363840.

The previous prime is 2585344350067. The next prime is 2585344350077. The reversal of 2585344350071 is 1700534435852.

It is a cyclic number.

It is not a de Polignac number, because 2585344350071 - 22 = 2585344350067 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2585344349998 and 2585344350025.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2585344350077) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 75388106 + ... + 75422391.

It is an arithmetic number, because the mean of its divisors is an integer number (193037437440).

Almost surely, 22585344350071 is an apocalyptic number.

2585344350071 is a deficient number, since it is larger than the sum of its proper divisors (503254648969).

2585344350071 is a wasteful number, since it uses less digits than its factorization.

2585344350071 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 150810614.

The product of its (nonzero) digits is 2016000, while the sum is 47.

The spelling of 2585344350071 in words is "two trillion, five hundred eighty-five billion, three hundred forty-four million, three hundred fifty thousand, seventy-one".

Divisors: 1 7 31 79 217 553 2449 17143 150810497 1055673479 4675125407 11914029263 32725877849 83398204841 369334907153 2585344350071