Base | Representation |
---|---|
bin | 100101101010000101100… |
… | …111100010110000011001 |
3 | 100011101121001220210021212 |
4 | 211222011213202300121 |
5 | 314344314341013042 |
6 | 5300454025112505 |
7 | 354651252321026 |
oct | 45520547426031 |
9 | 10141531823255 |
10 | 2587812047897 |
11 | 90853748959a |
12 | 359651028735 |
13 | 15a0501307ab |
14 | 8d37218c54d |
15 | 474acd50482 |
hex | 25a859e2c19 |
2587812047897 has 2 divisors, whose sum is σ = 2587812047898. Its totient is φ = 2587812047896.
The previous prime is 2587812047869. The next prime is 2587812047903. The reversal of 2587812047897 is 7987402187852.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2198150203456 + 389661844441 = 1482616^2 + 624229^2 .
It is a cyclic number.
It is not a de Polignac number, because 2587812047897 - 28 = 2587812047641 is a prime.
It is not a weakly prime, because it can be changed into another prime (2587812047827) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1293906023948 + 1293906023949.
It is an arithmetic number, because the mean of its divisors is an integer number (1293906023949).
Almost surely, 22587812047897 is an apocalyptic number.
It is an amenable number.
2587812047897 is a deficient number, since it is larger than the sum of its proper divisors (1).
2587812047897 is an equidigital number, since it uses as much as digits as its factorization.
2587812047897 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 126443520, while the sum is 68.
The spelling of 2587812047897 in words is "two trillion, five hundred eighty-seven billion, eight hundred twelve million, forty-seven thousand, eight hundred ninety-seven".
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