Base | Representation |
---|---|
bin | 1111000101010111000… |
… | …1001101001011010011 |
3 | 220202212200222120000010 |
4 | 3301111301031023103 |
5 | 13221203033001042 |
6 | 315013525130003 |
7 | 24502441105104 |
oct | 3612561151323 |
9 | 822780876003 |
10 | 259137000147 |
11 | 9a999098743 |
12 | 42280559903 |
13 | 1b58a038c5c |
14 | c7840ca3ab |
15 | 6b1a05859c |
hex | 3c55c4d2d3 |
259137000147 has 4 divisors (see below), whose sum is σ = 345516000200. Its totient is φ = 172758000096.
The previous prime is 259137000127. The next prime is 259137000181. The reversal of 259137000147 is 741000731952.
It is a semiprime because it is the product of two primes.
It is a de Polignac number, because none of the positive numbers 2k-259137000147 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (259137000107) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 43189500022 + ... + 43189500027.
It is an arithmetic number, because the mean of its divisors is an integer number (86379000050).
Almost surely, 2259137000147 is an apocalyptic number.
259137000147 is a deficient number, since it is larger than the sum of its proper divisors (86379000053).
259137000147 is an equidigital number, since it uses as much as digits as its factorization.
259137000147 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 86379000052.
The product of its (nonzero) digits is 52920, while the sum is 39.
The spelling of 259137000147 in words is "two hundred fifty-nine billion, one hundred thirty-seven million, one hundred forty-seven", and thus it is an aban number.
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