Base | Representation |
---|---|
bin | 100101110011101010000… |
… | …000000000001100110011 |
3 | 100012101010002101112101011 |
4 | 211303222000000030303 |
5 | 320031340021204042 |
6 | 5305313322051351 |
7 | 355463665416544 |
oct | 45635200001463 |
9 | 10171102345334 |
10 | 2598086116147 |
11 | 911929976095 |
12 | 35b639949b57 |
13 | 15acc9839712 |
14 | 8da688944cb |
15 | 478aece8a17 |
hex | 25cea000333 |
2598086116147 has 2 divisors, whose sum is σ = 2598086116148. Its totient is φ = 2598086116146.
The previous prime is 2598086115973. The next prime is 2598086116177. The reversal of 2598086116147 is 7416116808952.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2598086116147 - 231 = 2595938632499 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2598086116091 and 2598086116100.
It is not a weakly prime, because it can be changed into another prime (2598086116177) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1299043058073 + 1299043058074.
It is an arithmetic number, because the mean of its divisors is an integer number (1299043058074).
Almost surely, 22598086116147 is an apocalyptic number.
2598086116147 is a deficient number, since it is larger than the sum of its proper divisors (1).
2598086116147 is an equidigital number, since it uses as much as digits as its factorization.
2598086116147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5806080, while the sum is 58.
The spelling of 2598086116147 in words is "two trillion, five hundred ninety-eight billion, eighty-six million, one hundred sixteen thousand, one hundred forty-seven".
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