Base | Representation |
---|---|
bin | 11000010000001001… |
… | …111110001111100001 |
3 | 2111012211110102100120 |
4 | 120100021332033201 |
5 | 411312424302343 |
6 | 15544001510453 |
7 | 1611213413415 |
oct | 302011761741 |
9 | 74184412316 |
10 | 26040853473 |
11 | 10053423708 |
12 | 5069042429 |
13 | 25c007884b |
14 | 13906cad45 |
15 | a26273683 |
hex | 61027e3e1 |
26040853473 has 4 divisors (see below), whose sum is σ = 34721137968. Its totient is φ = 17360568980.
The previous prime is 26040853459. The next prime is 26040853519. The reversal of 26040853473 is 37435804062.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 26040853473 - 25 = 26040853441 is a prime.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (26040853973) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4340142243 + ... + 4340142248.
It is an arithmetic number, because the mean of its divisors is an integer number (8680284492).
Almost surely, 226040853473 is an apocalyptic number.
It is an amenable number.
26040853473 is a deficient number, since it is larger than the sum of its proper divisors (8680284495).
26040853473 is an equidigital number, since it uses as much as digits as its factorization.
26040853473 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8680284494.
The product of its (nonzero) digits is 483840, while the sum is 42.
The spelling of 26040853473 in words is "twenty-six billion, forty million, eight hundred fifty-three thousand, four hundred seventy-three".
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