Base | Representation |
---|---|
bin | 1011110111110000110011… |
… | …10001001001101010110011 |
3 | 10102102122012022021211122022 |
4 | 11323320121301021222303 |
5 | 11410202014321241042 |
6 | 131304325555302055 |
7 | 5333020161614462 |
oct | 573703161115263 |
9 | 112378168254568 |
10 | 26105243540147 |
11 | 8355198463942 |
12 | 2b174552aa92b |
13 | 11749385a2135 |
14 | 6637016469d9 |
15 | 3040cd569cd2 |
hex | 17be19c49ab3 |
26105243540147 has 4 divisors (see below), whose sum is σ = 26158847736816. Its totient is φ = 26051639343480.
The previous prime is 26105243540087. The next prime is 26105243540161. The reversal of 26105243540147 is 74104534250162.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 26105243540147 - 28 = 26105243539891 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 26105243540098 and 26105243540107.
It is not an unprimeable number, because it can be changed into a prime (26105243548147) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 26802097604 + ... + 26802098577.
It is an arithmetic number, because the mean of its divisors is an integer number (6539711934204).
Almost surely, 226105243540147 is an apocalyptic number.
26105243540147 is a deficient number, since it is larger than the sum of its proper divisors (53604196669).
26105243540147 is an equidigital number, since it uses as much as digits as its factorization.
26105243540147 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 53604196668.
The product of its (nonzero) digits is 806400, while the sum is 44.
The spelling of 26105243540147 in words is "twenty-six trillion, one hundred five billion, two hundred forty-three million, five hundred forty thousand, one hundred forty-seven".
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