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26125650433 is a prime number
BaseRepresentation
bin11000010101001101…
…011100101000000001
32111102202000112220201
4120111031130220001
5412001131303213
620000231205201
71613263236031
oct302515345001
974382015821
1026125650433
1110097280943
125091516801
1326047c846c
14139ba818c1
15a2d9236dd
hex61535ca01

26125650433 has 2 divisors, whose sum is σ = 26125650434. Its totient is φ = 26125650432.

The previous prime is 26125650403. The next prime is 26125650437. The reversal of 26125650433 is 33405652162.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13944775744 + 12180874689 = 118088^2 + 110367^2 .

It is a cyclic number.

It is not a de Polignac number, because 26125650433 - 25 = 26125650401 is a prime.

It is a super-2 number, since 2×261256504332 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 26125650392 and 26125650401.

It is not a weakly prime, because it can be changed into another prime (26125650437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 13062825216 + 13062825217.

It is an arithmetic number, because the mean of its divisors is an integer number (13062825217).

Almost surely, 226125650433 is an apocalyptic number.

It is an amenable number.

26125650433 is a deficient number, since it is larger than the sum of its proper divisors (1).

26125650433 is an equidigital number, since it uses as much as digits as its factorization.

26125650433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 129600, while the sum is 37.

The spelling of 26125650433 in words is "twenty-six billion, one hundred twenty-five million, six hundred fifty thousand, four hundred thirty-three".