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2613140473 is a prime number
BaseRepresentation
bin1001101111000001…
…0101101111111001
320202010002021211111
42123300111233321
520322430443343
61111144400321
7121520220226
oct23360255771
96663067744
102613140473
111121060129
1260b1760a1
133284c4088
141ab0a294d
15104628c9d
hex9bc15bf9

2613140473 has 2 divisors, whose sum is σ = 2613140474. Its totient is φ = 2613140472.

The previous prime is 2613140459. The next prime is 2613140477. The reversal of 2613140473 is 3740413162.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2074529209 + 538611264 = 45547^2 + 23208^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2613140473 is a prime.

It is not a weakly prime, because it can be changed into another prime (2613140477) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1306570236 + 1306570237.

It is an arithmetic number, because the mean of its divisors is an integer number (1306570237).

Almost surely, 22613140473 is an apocalyptic number.

It is an amenable number.

2613140473 is a deficient number, since it is larger than the sum of its proper divisors (1).

2613140473 is an equidigital number, since it uses as much as digits as its factorization.

2613140473 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12096, while the sum is 31.

The square root of 2613140473 is about 51118.8856783870. The cubic root of 2613140473 is about 1377.3815209203.

The spelling of 2613140473 in words is "two billion, six hundred thirteen million, one hundred forty thousand, four hundred seventy-three".