Base | Representation |
---|---|
bin | 111011011101110100000101… |
… | …110000000110110101111011 |
3 | 1021022000100210002011220112012 |
4 | 323131310011300012311323 |
5 | 233234431142223133342 |
6 | 2324122503305240135 |
7 | 106042113633654053 |
oct | 7335640560066573 |
9 | 1238010702156465 |
10 | 261533540052347 |
11 | 7637282a215572 |
12 | 253bab5149304b |
13 | b2c1678b69994 |
14 | 4882410258563 |
15 | 203814a7d4b82 |
hex | eddd05c06d7b |
261533540052347 has 4 divisors (see below), whose sum is σ = 261534802139976. Its totient is φ = 261532277964720.
The previous prime is 261533540052311. The next prime is 261533540052349. The reversal of 261533540052347 is 743250045335162.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 261533540052347 - 28 = 261533540052091 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 261533540052295 and 261533540052304.
It is not an unprimeable number, because it can be changed into a prime (261533540052349) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 630732929 + ... + 631147442.
It is an arithmetic number, because the mean of its divisors is an integer number (65383700534994).
Almost surely, 2261533540052347 is an apocalyptic number.
261533540052347 is a deficient number, since it is larger than the sum of its proper divisors (1262087629).
261533540052347 is a wasteful number, since it uses less digits than its factorization.
261533540052347 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1262087628.
The product of its (nonzero) digits is 9072000, while the sum is 50.
The spelling of 261533540052347 in words is "two hundred sixty-one trillion, five hundred thirty-three billion, five hundred forty million, fifty-two thousand, three hundred forty-seven".
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