Base | Representation |
---|---|
bin | 1111010111100000010… |
… | …0010001111001010011 |
3 | 221020110010111010210002 |
4 | 3311320010101321103 |
5 | 13311141343032401 |
6 | 321141110400215 |
7 | 25034230545536 |
oct | 3657004217123 |
9 | 836403433702 |
10 | 264007392851 |
11 | a1a68321884 |
12 | 431bb66006b |
13 | 1bb85088a27 |
14 | cac6c90a1d |
15 | 6d0290ca6b |
hex | 3d78111e53 |
264007392851 has 2 divisors, whose sum is σ = 264007392852. Its totient is φ = 264007392850.
The previous prime is 264007392797. The next prime is 264007392871. The reversal of 264007392851 is 158293700462.
264007392851 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 264007392851 - 210 = 264007391827 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 264007392796 and 264007392805.
It is not a weakly prime, because it can be changed into another prime (264007392871) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 132003696425 + 132003696426.
It is an arithmetic number, because the mean of its divisors is an integer number (132003696426).
It is a 1-persistent number, because it is pandigital, but 2⋅264007392851 = 528014785702 is not.
Almost surely, 2264007392851 is an apocalyptic number.
264007392851 is a deficient number, since it is larger than the sum of its proper divisors (1).
264007392851 is an equidigital number, since it uses as much as digits as its factorization.
264007392851 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 725760, while the sum is 47.
The spelling of 264007392851 in words is "two hundred sixty-four billion, seven million, three hundred ninety-two thousand, eight hundred fifty-one".
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