Base | Representation |
---|---|
bin | 11000100101101000… |
… | …110010000010101001 |
3 | 2112010221121112111112 |
4 | 120211220302002221 |
5 | 413032210021442 |
6 | 20043434240105 |
7 | 1623150635465 |
oct | 304550620251 |
9 | 75127545445 |
10 | 26401251497 |
11 | 10218900015 |
12 | 5149886035 |
13 | 264993280a |
14 | 13c65034a5 |
15 | a47c13082 |
hex | 625a320a9 |
26401251497 has 2 divisors, whose sum is σ = 26401251498. Its totient is φ = 26401251496.
The previous prime is 26401251439. The next prime is 26401251517. The reversal of 26401251497 is 79415210462.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 24872128681 + 1529122816 = 157709^2 + 39104^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-26401251497 is a prime.
It is not a weakly prime, because it can be changed into another prime (26401250497) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 13200625748 + 13200625749.
It is an arithmetic number, because the mean of its divisors is an integer number (13200625749).
Almost surely, 226401251497 is an apocalyptic number.
It is an amenable number.
26401251497 is a deficient number, since it is larger than the sum of its proper divisors (1).
26401251497 is an equidigital number, since it uses as much as digits as its factorization.
26401251497 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 120960, while the sum is 41.
The spelling of 26401251497 in words is "twenty-six billion, four hundred one million, two hundred fifty-one thousand, four hundred ninety-seven".
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