Base | Representation |
---|---|
bin | 1111010111100110001… |
… | …1100001101010011001 |
3 | 221020111212110122210112 |
4 | 3311321203201222121 |
5 | 13311214241023423 |
6 | 321143401454105 |
7 | 25034653016363 |
oct | 3657143415231 |
9 | 836455418715 |
10 | 264032361113 |
11 | a1a80425904 |
12 | 43207aa1335 |
13 | 1bb8a2bb651 |
14 | caca30dd33 |
15 | 6d04be0a78 |
hex | 3d798e1a99 |
264032361113 has 2 divisors, whose sum is σ = 264032361114. Its totient is φ = 264032361112.
The previous prime is 264032361059. The next prime is 264032361149. The reversal of 264032361113 is 311163230462.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 263177208064 + 855153049 = 513008^2 + 29243^2 .
It is a cyclic number.
It is not a de Polignac number, because 264032361113 - 218 = 264032098969 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 264032361113.
It is not a weakly prime, because it can be changed into another prime (264032361163) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 132016180556 + 132016180557.
It is an arithmetic number, because the mean of its divisors is an integer number (132016180557).
Almost surely, 2264032361113 is an apocalyptic number.
It is an amenable number.
264032361113 is a deficient number, since it is larger than the sum of its proper divisors (1).
264032361113 is an equidigital number, since it uses as much as digits as its factorization.
264032361113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 15552, while the sum is 32.
Adding to 264032361113 its reverse (311163230462), we get a palindrome (575195591575).
The spelling of 264032361113 in words is "two hundred sixty-four billion, thirty-two million, three hundred sixty-one thousand, one hundred thirteen".
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