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2640435241 = 2831993239
BaseRepresentation
bin1001110101100001…
…1101100000101001
320211000110000012211
42131120131200221
520401422411431
61114001405121
7122301220633
oct23530354051
96730400184
102640435241
111135503094
126183397a1
1333105c922
141b0969a53
15106c1b2b1
hex9d61d829

2640435241 has 4 divisors (see below), whose sum is σ = 2640556800. Its totient is φ = 2640313684.

The previous prime is 2640435211. The next prime is 2640435251. The reversal of 2640435241 is 1425340462.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 2640435241 - 25 = 2640435209 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2640435211) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18301 + ... + 74938.

It is an arithmetic number, because the mean of its divisors is an integer number (660139200).

Almost surely, 22640435241 is an apocalyptic number.

It is an amenable number.

2640435241 is a deficient number, since it is larger than the sum of its proper divisors (121559).

2640435241 is an equidigital number, since it uses as much as digits as its factorization.

2640435241 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 121558.

The product of its (nonzero) digits is 23040, while the sum is 31.

The square root of 2640435241 is about 51385.1655733442. The cubic root of 2640435241 is about 1382.1605938367.

The spelling of 2640435241 in words is "two billion, six hundred forty million, four hundred thirty-five thousand, two hundred forty-one".

Divisors: 1 28319 93239 2640435241